(I)    ABC - DEF  = EG
        +      -     :
(II)   HIE : DAH  =  H
       ---------------
(III)  FBD :  HB  = DF
       (IV)   (V)  (VI)


Solution:
(II)   leading digits H >= D * H > 0  =>  1 >= D > 0  =>  D = 1.
(I.3)  A = D + 1  =>  A = 2
(II.2) I > A = 2  =>  I != 0
(IV.2) I = 9  (I=0 is already excluded)
(II)   100 > (20+H) * H > 90  =>  H = 4
(II)   496 = 124 * 4  =>  E = 6
(VI)   60 + G = 4 * (10 + F)  =>  20 + G = 4*F  =>  G is a multiple of 4
       so (G,H) are (0,5), (4,6), or (8,7).
As G=0 is impossible from (I.1) and H=6 is impossible as E=6 we get
G = 8 and H = 7.
(I)    235 = 167 + 68  =>  B = 3, C = 5.


       235 - 167  = 68
        +      -     :
       496 : 124  =  4
       ----------------
       731 :  43  = 17


References:

Eckstein;
  Symbolrätsel,
  www.eckstein.de