(I)     EGA  *    AH  =  DGFG
         *        +        -
(II)     LL  +  EFFC  =  EFDL
       ----------------------
(III)  ABCD  +  EFGH  =  KLBK
       (IV)      (V)     (VI)


Solution:
From (V.1) or (II.1) follows C=0.
(V.2)   A + F = G  =>  A < G
(II.2)  L + F = D
(IV)    L < A      =>  L < G
(VI.1)  L + K = G   as L < G
(VI.3)  L + F + 1 = G  with carry otherwise we had K = F. So F + 1 = K
(VI.2)  B + D = F + 10
(VI.4)  K + E = D
(III.2) G + 1 = B      with carry
(III.1) D + H = K + 10
(III.3) B + F = G + F + 1 = L + 10  as L < G
(III.4) A + E + 1 = K
(VI.3) + (III.3)  2F + 2 = 10  =>  F=4, K=5
(II.2) - (VI.3)   G = D + 1 => B = D + 2
(V.2) - (II.2)    A = L + 1
plug in B=D+2 in (VI.2) we get D=6, G=7, B=8.
Now from (II.2) or (V.2) we get L=2, A=3.
Then (III) gives E=1 and H=9.

        173  *    39  =  6747
         *        +        -
         22  +  1440  =  1462
       ----------------------
       3806  +  1479  =  5285


References:

Hoer Zu, No 00, 1995