P153: A Prime Proof Prove that whenever P and P*P+2 are both primes, P*P+4 is also prime. (P+2 is prime too (Torsten).) Variation I: (Torsten Sillke) Prove that whenever P and P^4-6 are both primes, P^4+6 is also prime. Variation II: (Torsten Sillke) Prove that whenever P, P^3-6, and P^3+6 are all primes, P^2-2 is also prime. A puzzle from: Angela Fox Dunn, Second Book of Mathematical Bafflers, Dover Publ., 1983 -------------------------------------------------------------------- Hint Allert Hint: A Prime Proof: The number 3 is the key. Variation I: The number 5 is the key. Variation II: The number 7 is the key. Generalization: --------------- (A) Let q be a prime then for each integer n we have: q | n or q | n^(q-1) + (q-1) This is the little theorem of Fermat. Therefore the set { n | n and n^(q-1) + (q-1) are primes } is a subset of {q}. Application: q=3: { n | n and n*n + 2 are primes } = {3} q=5: { n | n and n^4 + 4 are primes } = {} (B) Let q be an odd prime then for each integer n we have: q | n or q | n^((q-1)/2) + (q-1) or q | n^((q-1)/2) - (q-1) Application: q=7: { n | n and n^3 + 6 and n^3 - 6 are primes } = {7} Reference: Hon73: Ross Honsberger; Mathematical Gems I, The Dolciani Mathematical Expositions No. 1 The Mathematical Association of America, 1973 (german: Mathematische Edelsteine, Vieweg, 1981) - Chapter 1: an old chinease theorem and Pierre de Fermat -- http://www.mathematik.uni-bielefeld.de/~sillke/ mailto:Torsten.Sillke@uni-bielefeld.de