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<TITLE>The Photo Paradox: G(65536)</TITLE>
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<b>G(256<sup>2</sup></b>)
<br><br><br>
Reminder: <b>G(256<sup>2</sup></b>) is the maximal order 
<br> of a pixel permutation of a 256 x 256 pixel picture.
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<b>G(256<sup>2</sup></b>) 
<br>
= 2<sup>7</sup> x 3<sup>4</sup> x 5<sup>3</sup> x 7<sup>2</sup>
 x ... x 17<sup>2</sup> x 19 x  ... x 919 / 907
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= 24107436976929288463522986071862342451920273240564393170920449
41819955017519554578670604824873470865661872414524190177858342
65810636097626119129793375231971546144439537240529785712677123
75617172897001141282081020394958233219985347683711985830591320
97143165812673014110760283636094768695580586056307187638991355
13034355181542914923156693580802071057037000102142542231397876
08931762989456000
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still a quite large number: there are 389 decimal digits.
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The calculation is due to Jean-Louis Nicolas, Universit&eacute; Claude Bernard (Lyon 1),
<br> see http://math.univ-lyon1.fr/~nicolas/landaug.html
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