(I) ABC - DEF = EG
+ - :
(II) HIE : DAH = H
---------------
(III) FBD : HB = DF
(IV) (V) (VI)
Solution:
(II) leading digits H >= D * H > 0 => 1 >= D > 0 => D = 1.
(I.3) A = D + 1 => A = 2
(II.2) I > A = 2 => I != 0
(IV.2) I = 9 (I=0 is already excluded)
(II) 100 > (20+H) * H > 90 => H = 4
(II) 496 = 124 * 4 => E = 6
(VI) 60 + G = 4 * (10 + F) => 20 + G = 4*F => G is a multiple of 4
so (G,H) are (0,5), (4,6), or (8,7).
As G=0 is impossible from (I.1) and H=6 is impossible as E=6 we get
G = 8 and H = 7.
(I) 235 = 167 + 68 => B = 3, C = 5.
235 - 167 = 68
+ - :
496 : 124 = 4
----------------
731 : 43 = 17
References:
Eckstein;
Symbolrätsel,
www.eckstein.de