(I)    ABCD  +  EFCF  =  BGHE
         -        :        +
(II)   AAIF  +   GDE  =  AEDC
       ----------------------
(III)   FCH  *    GK  =  KHHI
       (IV)      (V)     (VI)


Solution:
(VI.2)  D is 0 or 9
(IV.2)  I is 0 or 9
(I.1)   D is not 0
Therefore I=0 and D=9.
(IV.3)  A + F     = B
(I.4)   A + E + 1 = B  with carry, otherwise E = F.
That is F = E + 1
(II.1)  F + E = C
(VI.1)  E + C = 10
Eliminate C and F gives
 3E + 1 = 10  =>  E = 3 and then F = 4.
(VI.1)  C = 7
(IV.1)  H = 5
(VI.3)  G = 1
(II.3)  A = 2
(IV.3)  B = 6
(VI.4)  K = 8


      2679  +  3474  =  6153
        -        :        +
      2204  +   193  =  2397
      ----------------------
       475  *    18  =  8550


References:

Hoer Zu, No 01, 2003-12-23