(I) ABCD + EFCF = BGHE
- : +
(II) AAIF + GDE = AEDC
----------------------
(III) FCH * GK = KHHI
(IV) (V) (VI)
Solution:
(VI.2) D is 0 or 9
(IV.2) I is 0 or 9
(I.1) D is not 0
Therefore I=0 and D=9.
(IV.3) A + F = B
(I.4) A + E + 1 = B with carry, otherwise E = F.
That is F = E + 1
(II.1) F + E = C
(VI.1) E + C = 10
Eliminate C and F gives
3E + 1 = 10 => E = 3 and then F = 4.
(VI.1) C = 7
(IV.1) H = 5
(VI.3) G = 1
(II.3) A = 2
(IV.3) B = 6
(VI.4) K = 8
2679 + 3474 = 6153
- : +
2204 + 193 = 2397
----------------------
475 * 18 = 8550
References:
Hoer Zu, No 01, 2003-12-23