(I) HEB + EUS = LFS - - : (II) WUB : EH = US ------------------ (III) EHB - ESU = RA (IV) (V) (VI) Solution: (IV.1) B = 0 (V) E + U <= S (V.1) S + H = U + 10 as S > U (V.2) U + E + 1 = S (IV) E + W <= H (IV.2) H + U = E + 10 as H > E (V.1)+(V.2)+(IV.2) 2E + 1 = U Now we show that E>=2 is impossible. (II) E*U <= W If E>=2 then 2*5 <= E*U <= W but 10<=W is impossible. Knowing E=1, U=3 this puzzles is easily solved. (V.2) S = 5 (V.1) H = 8 (IV) W = 6 (I) F=4, L=9 (III) A=7, R=7 810 + 135 = 945 - - : 630 : 18 = 35 ---------------- 180 - 153 = 27 Ordering the letters by their encoded digit we get 0123456789 BERUFSWAHL References: Boris A. Kordemsky; Köpfchen muss man haben, Aulis Verlag Deubner Köln, 1975, ISBN 3-7614-0315-1 Problem 241.2