S I X + S I X + S I X = N I N E + N I N E
Solution:
This one is simple case checking.
First NINE < 1500. So N=1 and 0<=I<4.
N I NIN 2/3 NIN
1 0 101 67.333
1 1 111 74.000
1 2 121 80.666
1 3 131 87.333
1 4 141 94.000
We see that only I=4 gives possible I for SIX.
As 3 | NINE we have to try 1410, 1413, 1416, 1419 to check.
These give 940, 942, 944, 946. Only E=3 gives a valid solution.
942 + 942 + 942 = 1413 + 1413
References:
- Author: Alan Wayne
- Martin Gardner;
Sci. Am. (Sep. 1975)
- Martin Gardner;
The Magic Numbers of Dr. Matrix, 1985
Chap. 18: The King James Bible